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function isInteger(para) '判断数字是否整形
on error resume next
dim str
dim l,i
if isNUll(para) then
isInteger=false
exit function
end if
str=cstr(para)
if trim(str)="" then
isInteger=false
exit function
end if
l=len(str)
for i=1 to l
if mid(str,i,1)>"9" or mid(str,i,1)<"0" then
isInteger=false
exit function
end if
next
isInteger=true
if err.number<>0 then err.clear
end function
on error resume next
dim str
dim l,i
if isNUll(para) then
isInteger=false
exit function
end if
str=cstr(para)
if trim(str)="" then
isInteger=false
exit function
end if
l=len(str)
for i=1 to l
if mid(str,i,1)>"9" or mid(str,i,1)<"0" then
isInteger=false
exit function
end if
next
isInteger=true
if err.number<>0 then err.clear
end function


2009
16:05
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